{"id":71085,"date":"2025-02-03T10:13:00","date_gmt":"2025-02-03T10:13:00","guid":{"rendered":"https:\/\/www.ginx.tv\/vejrgang-wins-ea-fc-pro-25-open-finals"},"modified":"2025-02-03T10:19:10","modified_gmt":"2025-02-03T10:19:10","slug":"vejrgang-wins-ea-fc-pro-25-open-finals","status":"publish","type":"post","link":"https:\/\/www.ginx.tv\/en\/video-games\/vejrgang-wins-ea-fc-pro-25-open-finals","title":{"rendered":"Vejrgang Wins EA FC Pro 25 Open Finals"},"content":{"rendered":"
With a prize pool of over $500,000 and a spot at the World Championships on the line, 12 players battled it out in front of a live audience in the heart of London, UK on February 1, 2025. With a single elimination bracket format, the stakes couldn’t have been higher. <\/p>\n
Finals day opened with the Knockout Stage where match-ups saw KTzn take on EWC winner Jafonso, nicolas99fc against Yuval, LJR Peixoto with Emre Yilmaz, and World Ranking No. 1 Abu Makkah duke it out against FacuCowen. For four hopefuls, it was the end of the road, but for Jafonso, nicolas99fc, LJR Peixoto, and Abu Makkah the next stop was the Quarterfinals. <\/p>\n
In what were sure to be some of the most entertaining matches of the night, the Quarterfinals saw the following match-ups:<\/p>\n
With the hard-fighting losing players now out of the tournament, but having secured their space at Worlds, it was time for the Semi-Finals:<\/p>\n
Both matches, though over in what seemed like a flash, were close. Victory was poised for either side, but ultimately our final showdown was:<\/p>\n
Anders “Vejrgang” Vejrgang, the 19 year-old from Danish player for RBLZ Gaming and the FC Pro 24 World Championship, would face-off against the 23 year-old Italian player for exeed, Obrun2002. Both players were hungry for the trophy, but had approached the match with very different personalities. Vejrgang had arguably been the most animated of the tournament with plenty to say to the cameras, and the audience. Obrun, however, took a calmer approach, appearing stoic throughout the Final. <\/p>\n